Hi, the last part of this week's lecture will consist of understanding filtered back projection
a bit better by seeing it in action. Here you can see again the formula for filtered
back projection. So given data acquired from X-ray tomography, I'm sorry my nose is a bit
congested today, I hope you can understand me a little less. So given the random transform
of some intensity field F, which is what X-ray tomography outputs, so this is the raw data
from a CT scan for example, how do you get back the image hidden in here? And the formula
we have derived as follows, what you have to do is apply this pipeline and we look at
this pipeline a bit more closely. And what you have to do is you take RF, the X-ray data,
you put this into Fourier space by applying the one dimensional Fourier transform, then
you apply a high pass filter, then you go back to the actual space via an inverse Fourier
transform and then you do back projection in the way we have understood so far. And
let's now see how this works. I've shown you this before, so this is the image we're
looking at, this is just an L-shaped object inside this X-ray machine, left marked this
edge for orientation purposes. And the forward round-trips form looks at this image via slices
for a given angle and it accumulates intensity along this line. So for example if we take
angle zero then you take vertical slices through this image and you can see that there's a
lot of intensity attenuation here and a little bit here and nothing at the boundary of course.
And rotating this gives you all those slices in the sinogram. So for example for angle
34 degrees which corresponds to this rotated image here, you get this shape here and this
is this black slice inside the sinogram. And I always mark the position of this edge here
in red. So again, different angle looks like this, different angle looks like this, you
can see that we're exploring the whole sinogram that way. So we're looking at this two-dimensional
data set, a sinogram, angle slice by angle slice. And we talked about how this could
in principle be inverted naively with back projection. So you take such a slice and you
project this mass here upwards and you distribute it along this direction and this is what you
can see here. For example for angle 56 you take this sinogram and you smear it out like
this along the image. And if you do this for all the angles and you add up all those smeared
back projected contributions you get this blurry image of L which is okay but not perfect
and you can't make out fine details anymore. Now filter back projection, what do we do?
First we have to go into Fourier space, apply a filter and then go back. So what you do
is you take the sinogram, this is the sinogram here and first you have to take one dimensional
Fourier transforms. This is what you can see here. So this is an image of only the real
part of the Fourier transform of the sinogram. So this is taking the sinogram and taking
the one dimensional Fourier transform in every slice. Now you apply this high pass filter,
this is what's happening here, and this turns this image into this image here. So as you
can see there is structure hidden in here which you can't see but if you amplify with
this high pass filter this just gets visible. And when you go back to the actual space by
one dimensional inverse Fourier transform you get this image here. And as you can see
I hope the quality is alright, you can now compare this, let's maybe put these side by
side, let me do this for a second. Okay so that's it, you can see the original sinogram
here, sorry here, and the filtered version we have just acquired is this one. So as you
can see this kind of only looks at the edges inside the sinogram. So what we've done is
we've taken this, applied a high pass filter and we get this sinogram here. This is not
the original sinogram, this is not the data that you get from a CT scan but it's now a
filtered CT scan, a filtered sinogram. If you now take, so if you take the original sinogram
and you do back projection then you get this reconstruction here which is bad because it's
too blurry. But if you take the filtered sinogram and you do back projection then you get this
here. So you take all the slices through the one dimensional, sorry the slice through the
filtered sinogram, these look like that, so this is a slice through the filtered sinogram,
you back project like this and you accumulate that for all angles that you can have then
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00:08:27 Min
Aufnahmedatum
2022-01-10
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2022-01-10 14:06:03
Sprache
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